0=8x^2-40x+32

Solution for 0=8x^2-40x+32 equation:

0=8x^2-40x+32

We move all terms to the left:

0-(8x^2-40x+32)=0

We add all the numbers together, and all the variables

-(8x^2-40x+32)=0

We get rid of parentheses

-8x^2+40x-32=0

a = -8; b = 40; c = -32;
Δ = b2-4ac
Δ = 402-4·(-8)·(-32)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-24}{2*-8}=\frac{-64}{-16}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+24}{2*-8}=\frac{-16}{-16}
=1
$